3[s+3(s-1)]=18

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Solution for 3[s+3(s-1)]=18 equation:


Simplifying
3[s + 3(s + -1)] = 18

Reorder the terms:
3[s + 3(-1 + s)] = 18
3[s + (-1 * 3 + s * 3)] = 18
3[s + (-3 + 3s)] = 18

Reorder the terms:
3[-3 + s + 3s] = 18

Combine like terms: s + 3s = 4s
3[-3 + 4s] = 18
[-3 * 3 + 4s * 3] = 18
[-9 + 12s] = 18

Solving
-9 + 12s = 18

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 12s = 18 + 9

Combine like terms: -9 + 9 = 0
0 + 12s = 18 + 9
12s = 18 + 9

Combine like terms: 18 + 9 = 27
12s = 27

Divide each side by '12'.
s = 2.25

Simplifying
s = 2.25

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